Purchase orders between buyers and sellers. Free on Board (FOB) is a shipment term that defines the point in the supply chain when a buyer or seller becomes liable for the goods being transported.(a + b) × c and (a + b) × d Looking for online definition of B/C or what B/C stands for? B/C is listed in the World's largest and most authoritative dictionary database of abbreviations and acronyms The Free Dictionary (a +b)(c + d) = (a + b) × c + (a + b) ×d Now on each of the two i.e. 1 Answer Shwetank Mauria (a +b)(c + d) = ac + bc + ad + bd Explanation: To multiply (a +b)(c + d), let us first consider (a + b) as single number and applying distributive property.new search.O/B is listed in the World's largest and most authoritative dictionary database of abbreviations and acronyms. Ochoa & Clary (chemistry team) Note: We have 65 other definitions for O/C in our Acronym Attic. SHOP NOW: We are SO EXCITED to announce that English Tree TV PLUSH TOYS are AVAILABLE NOW! Head over to out shop here: "B.C." stands for "before Christ." The system labels years based on a traditional notion of when Jesus was born - with the "A.D." denoting years after his birth and "B.C." designating the.Order of the Carmelites (religious order) OC.Toms River, NJ 08753 Use our online Scrabble solver to unscramble the jumbled letters on your rack and maintain your winning streak in this fun word game. One of a kind hand dyed & printed apparel for adults & mini’s. The acronyms, possibly including some more recent additions, include: S.W.A.L.K. They were usually written on the back of an envelope. Us.Copy the code below and paste it where you want this content to be shown on your page or customize:World War II postal acronyms were first used to convey messages between servicemen and their sweethearts back home. Most common OBC abbreviation full forms updated in May 2023 The Letter B Song by Have Fun Teaching is a great way to learn all about the Letter B. What does OBC abbreviation stand for? List of 279 best OBC meaning forms based on popularity. Sebastian has pointed out), it makes one list (result of sorted()) then iterates over that list to create a result list. The get idiom not only looks up the dict twice (as J. ) for k in sorted(adict, key=adict.get, reverse=True)] sorted(eritems(), key=itemgetter(1), reverse=True) Putting them close together for ease of comparison: There was also mention of " the simplicity of the get idiom". The itemgetter answer is a clear winner on speed. These results are NOT "slightly" different. Repeating the experiment with range(-n,n+1) (Windows box, Python 2.6.4, all times in microseconds): A use case like what are the most frequent words in a text or most frequent names in a membership list or census involves much larger datasets. The differences in cost of the various methods are masked by the overhead. The currently accepted answer gives timing results which are based on a trivially small dataset (size = 6 - (-5) = 11). If you want to upvote anyone, upvote Nadia. Note: I'm putting this in as an answer so that it gets seen. In normal cases, where this operation is only one step within some bigger task and a microsecond more or less matters little, focusing on the simplicity of the get idiom is, however, also a reasonable alternative. In "bottleneck" cases, where those microsecond fractions are crucial to you, by all means do focus on that. get-based solution is smack midway in performance between the two items-based ones - slightly slower than the itemgetter, slightly faster than the lambda. $ python -mtimeit -s'adict=dict((x,x**2) for x in range(-5,6))' 'sorted(eritems(), key=lambda (k,v): v, reverse=True)'ġ00000 loops, best of 3: 11.5 usec per loop $ python -mtimeit -s'adict=dict((x,x**2) for x in range(-5,6)) from operator import itemgetter' 'sorted(eritems(), key=itemgetter(1), reverse=True)'ġ00000 loops, best of 3: 9.66 usec per loop Since you want key/value pairs, you could work on the items as all other answers suggest, or (to use the nifty adict.get bound method instead of itemgetters or weird lambdas -), ) for k in sorted(adict, key=adict.get, reverse=True)]Įdit: in terms of performance, there isn't much into it either way: $ python -mtimeit -s'adict=dict((x,x**2) for x in range(-5,6))' ') for k in sorted(adict, key=adict.get, reverse=True)]'ġ00000 loops, best of 3: 10.8 usec per loop A dict's keys, reverse-sorted by the corresponding values, can best be gotten as sorted(adict, key=adict.get, reverse=True)
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